INTRODUCTION Chapter 1 introduced basic concepts such as current, voltage, and power in an electric circuit. To actually determine the values of this variable in a given circuit requires that we understand some fundamental laws govern electric circuits. These laws known as Ohm’s law and Kirchhoff’s laws, from the foundation upon which electric circuit analysis is build. In this chapter, in addition to these laws we shall discuss some techniques commonly applied in circuit design and analysis. These techniques include combining resistors in series or parallel, voltage division, current division and delta-to-wye and wye-to-delta transformations

OHM’S LAW Materials in general have a characteristic behavior of resisting the flow of electric charge. This physical property or ability to resist current known as resistance and is represented by the symbol R. the resistance of any material with a uniform cross-sectional area A depends on A and its length l, as shown in (a). We can represent resistance (as measured in the laboratory), in mathematical form, R = ρ l A size 12{R=ρ { {l} over {A} } } {} where ρ size 12{ρ} {} is known as the resistivity of the material in ohm-meters. Good conductors, such as copper and aluminum, have low resistivities, while insulators, such as mica and paper, have high resistivities. presents the values of ρ size 12{ρ} {} for some common materials and shows which materials are used for conductors, insulators, and semiconductors. Resistivities of common materials. Material Resistivity ( Ωm size 12{ %OMEGA m} {}) Usage Silver 1 . 64 x 10 − 8 size 12{1 "." "64"x"10" rSup { size 8{ - 8} } } {} Conductor Copper 1 . 72 x 10 − 8 size 12{1 "." "72"x"10" rSup { size 8{ - 8} } } {} Conductor Aluminum 2 . 8x 10 − 8 size 12{2 "." 8x"10" rSup { size 8{ - 8} } } {} Conductor Gold 2 . 45 x 10 − 8 size 12{2 "." "45"x"10" rSup { size 8{ - 8} } } {} Conductor Carbon 4x 10 − 5 size 12{4x"10" rSup { size 8{ - 5} } } {} Semiconductor Germanium 47 x 10 − 2 size 12{"47"x"10" rSup { size 8{ - 2} } } {} Semiconductor Silicon 6 . 4x 10 2 size 12{6 "." 4x"10" rSup { size 8{2} } } {} Semiconductor Paper 10 10 size 12{"10" rSup { size 8{"10"} } } {} Insulator Mica 5x 10 11 size 12{5x"10" rSup { size 8{"11"} } } {} Insulator Glass 10 12 size 12{"10" rSup { size 8{"12"} } } {} Insulator Teflon 3x 10 12 size 12{3x"10" rSup { size 8{"12"} } } {} Insulator

a) Resistor b) Circuit symbol for resistance. The circuit element used to model the current-resisting behavior of a material is the resistor. For the purpose of constructing circuits, resistors are usually made from metallic alloys and carbon compounds. The circuit symbol for the resistor is shown in (b), where R stands for the resistance of the resistor. The resistor is the simplest passive element. Georg Simon Ohm (1787-1854), a German physicist, is credited with finding the relationship between current and voltage for a resistor. This relationship is known as Ohm’s law. Ohm’s law states that the voltage v across a resistor is directly proportional to the current i flowing through the resistor. That is, v ~ i size 12{v prop i} {} Ohm defined the constant of proportionality for a resistor to be the resistance, R. Thus, becomes v = iR size 12{v= ital "iR"} {} Which is the mathematical form of Ohm’s law. R in is measured in the unit of Ohms, designated Ω size 12{ %OMEGA } {}. Thus, The resistance R of an element denotes its ability to resist the flow of electric current; it is measured in ohms ( Ω size 12{ %OMEGA } {}). We may deduce from that R = v i size 12{R= { {v} over {i} } } {} So that 1 Ω size 12{ %OMEGA } {} = 1 V/A To apply Ohm’s law as stated in , we must pay careful attention to the current direction and voltage polarity. The direction of current i and the polarity of voltage v must conform with the passive sign convention, as shown in (b). This implies that current flows from a higher potential to a lower potential in order for v = iR. If current flows from a lower potential to a higher potential, v = -iR.

a) Short cicuit (R=0), b) Open circuit (R= ). Since the value of R can range from zero to infinity, it is important that we consider the two extreme possible values of R. An element with R = 0 is called a short circuit, as shown in (a). For a short circuit, v = iR = 0 size 12{v= ital "iR"=0} {} Showing that the voltage is zero but the current could be anything. In practice, a short circuit is usually a connecting wire assumed to be a perfect conductor. Thus, A short circuit is a circuit element with resistance approaching zero. Similarly, an element with R = ∞ size 12{ infinity } {} is known as an open circuit, as shown in (b). For an open circuit, i = lim R → ∞ v R = 0 size 12{i= {"lim"} cSub { size 8{R rightarrow infinity } } { {v} over {R} } =0} {} Indicating that the current is zero though the voltage could be anything. Thus, An open circuit is a circuit element with resistance approaching infinity.

Fixed resistor: a) wire-wound type, b) carbon film thin type. A resistor is either fixed or variable. Most resistors are of the fixed type, meaning their resistance remains constant. The two common types of fixed resistors (wirewound and composition) are shown in . The composition resistors are used when large resistance is needed. The circuit symbol in (b) is for a fixed resistor. Variable resistors have adjustable resistance. The symbol for a variable resistor is shown in (a). A common variable resistor is known as a potentiometer or pot for short, with the symbol shown in (b). The pot is three-terminal element with the sliding contact or wiper. By the sliding wiper, the resistances between the wiper terminal and the fixed terminals vary. Like fixed resistors, variable resistors can either be of wirewound or composition type, as shown in . Although resistors like those in and are used in circuit designs, today most circuit components including resistors are either surface mounted or integrated, as typically shown in .

Circuit symbol for: a) a variable resistor in general, b) a potentiometer.

Variable resistor: a) composition type, b) slider pot. It should be pointed out that not all resistors obey Ohm’s law. A resistor that obeys Ohm’s law is known as a linear resistor. It has a constant resistance and thus its current-voltage characteristic is as illustrated in (a): its i-v graph is a strait passing through the origin. A nonlinear resistor does not obey Ohm’s law. Its resistance varies with current and its i-v characteristic is typically shown in (b). Examples of devices with nonlinear resistance are the lightbulb and the diode. Although all practical resistors may exhibit nonlinear behavior under certain conditions, we will assume in this book that all elements actually designated as resistors are linear.

Resistors in a thin-film circuit.

The i-v charcteristic of: a) a linear resistor, b) a nonlinear resistor. A useful quantity in circuit analysis is the reciprocal of resistance R, known as conductance and denoted by G: G = 1 R = i v size 12{G= { {1} over {R} } = { {i} over {v} } } {} The conductance is a measure of how well an element will conduct electric current. The unit of conductance is the siemens (S), the SI unit of conductance: 1S = 1A / V size 12{1S=1A/V} {} Thus, Conductance is the ability of an element to conduct electric current; it is measured in siemens (S). The same resistance can be expressed in ohms or siemens. For example, 10 Ω size 12{ %OMEGA } {} is the same as 0.1 S. from , we may write i = Gv size 12{i= ital "Gv"} {} The power dissipated by a resistor can be expressed in term of R. using and , p = vi = i 2 R = v 2 R size 12{p= ital "vi"=i rSup { size 8{2} } R= { {v rSup { size 8{2} } } over {R} } } {} The power dissipated by a resistor may also be expressed in terms of G as p = vi = v 2 G = i 2 G size 12{p= ital "vi"=v rSup { size 8{2} } G= { {i rSup { size 8{2} } } over {G} } } {} We should note two things from and : 1. The power dissipated in a resistor is a nonlinear function of either current or voltage. 2. Since R and G are positive quantities, the power dissipated in a resistor is always positive. Thus, a resistor always absorbs power from the circuit. This confirms the idea that a resistor is a passive element, incapable of generating energy.

NODES, BRANCHES AND LOOPS Since the elements of an electric circuit can be interconnected in several ways, we used to understand some basic concepts of network topology. To differentiate between a circuit and a network, we may regard a network as an interconnection of elements or devices, whereas a circuit is a network providing one or more closed paths. The convention, when addressing network topology, is to use the word network and circuit mean the same thing when used in this context. Such elements include branches, nodes, and loops. A branch represents a single element such as a voltage source or a resistor. In the other words, a branch represents any two-terminal element. The circuit in has five branches, namely, the 10 V voltage source, the 2 A current source, and the three resistors. A node is the point of connection between two or more branches.

Nodes, branches, and loops. A node is usually indicated by a dot in a circuit. If a short circuit (a connecting wire) connects two nodes, the two nodes constitute a single node. The circuit in has three nodes a, b, and c. notice that the three points that form node b are connected by perfectly conducting wires and therefore constitute a single point. The same is true of the four points forming nodes c. we demonstrate that the circuit in has only three nodes by redrawing the circuit in . The two circuits in and are identical. However, for the sake of the clarity, nodes b and c are spread out with perfect conductors as in . A loop is any closed path in a circuit. A loop is a closed path formed by starting at a node, passing through any node more than one. A loop is said to be independent if it contains at least one branch which is not a part of any other independent loop. Independent loops or paths result in independent sets of equations.

Three node circuit of Figure 2.8 is redrawn. For example, the closed path abca containing the 2- Ω size 12{ %OMEGA } {} resistor in is a loop. Another loop is the closed path bcb containing the 3- Ω size 12{ %OMEGA } {} resistor and current source. Although one can identify six loops in , only three of them are independent. A network with b branches, n nodes, and l independent loops will satisfy the fundamental theorem of network topology: b = l + n - 1 As the next two definitions show, circuit topology is of great value to the study of voltages and currents in an electric circuit. Two or more elements in series if they exclusively share a single node and consequently carry the same current. Two more elements are in parallel if they are connected to the same two nodes and consequently have the same voltage across them. Elements are in series when they are chain-connected or connected sequentially, end to end. For example, two elements are in series if they share one common node and no other element is connected to that common node. Elements in parallel are connected to the same pair of terminals. Elements may be connected in a way that they are neither in series nor in parallel. In the circuit show in , the voltage source and the 5- Ω size 12{ %OMEGA } {} resistor are in series because the same current will flow through them. The 2- Ω size 12{ %OMEGA } {} resistor, the 3- Ω size 12{ %OMEGA } {} resistor, and the current source are in parallel because they are connected to the same two nodes (b and c) resistors and neither in series nor in parallel with each other.

KIRCHHOFF’S LAWS Ohm’s law is not sufficient to analyze circuits. However, when it is coupled with Kirchhoff’s two laws, we have a sufficient, powerful set of tools for analyzing a large variety of electric circuits. Kirchhoff’s laws were first introduced in 1847 by the German physicist Gustav Robet Kirchhoff (1824-1887). These laws are formally known as Kirchhoff’s current law (KCL) and Kirchhoff’s voltage law (KVL). Kirchhoff’s first law is based on the law of conservation of charge, which requires that the algebraic sum of charges within a system cannot change. Kirchhoff’s current law (KCL) states that the algebraic sum of currents entering a node (or a closed boundary) is zero. Mathematically, KCL implies that ∑ n = 1 N i n = 0 size 12{ Sum cSub { size 8{n=1} } cSup { size 8{N} } {i rSub { size 8{n} } =0} } {} Where N is number of branches connected to the node and in is nth current entering (or leaving) the node. By the law, current entering a node may be regarded as positive, while currents leaving the node may be taken as negative or vice versa. To prove KCL assume a set of currents ik(t) size 12{i rSub { size 8{k} } \( t \) } {}, k = 1, 2 … flow into a node. The algebraic sum of currents at the node is i T ( t ) = i 1 ( t ) + i 2 ( t ) + i 3 ( t ) + . . . size 12{i rSub { size 8{T} } \( t \) =i rSub { size 8{1} } \( t \) +i rSub { size 8{2} } \( t \) +i rSub { size 8{3} } \( t \) + "." "." "." } {} Integrating both sides of gives q T ( t ) = q 1 ( t ) + q 2 ( t ) + q 3 ( t ) + . . . size 12{q rSub { size 8{T} } \( t \) =q rSub { size 8{1} } \( t \) +q rSub { size 8{2} } \( t \) +q rSub { size 8{3} } \( t \) + "." "." "." } {} Where qk(t)=∫ik(t)dt size 12{q rSub { size 8{k} } \( t \) = Int {i rSub { size 8{k} } \( t \) ital "dt"} } {}and qT(t)=∫iT(t)dt size 12{q rSub { size 8{T} } \( t \) = Int {i rSub { size 8{T} } \( t \) ital "dt"} } {} but the law of conservation of electric charge requires that the algebraic sum of electric charges at the note must not change; that is, the node stores no net charge. Thus qT(t)=0→i(t)=0 size 12{q rSub { size 8{T} } \( t \) =0 rightarrow i \( t \) =0} {}, confirming the validity of KCL. Consider the node in . Applying KCL gives i 1 + ( − i 2 ) + i 3 + i 4 + ( − i 5 ) = 0 size 12{i rSub { size 8{1} } + \( - i rSub { size 8{2} } \) +i rSub { size 8{3} } +i rSub { size 8{4} } + \( - i rSub { size 8{5} } \) =0} {} Since current i1 size 12{i rSub { size 8{1} } } {}, i2 size 12{i rSub { size 8{2} } } {} and i4 size 12{i rSub { size 8{4} } } {} are entering the node, while current i2 size 12{i rSub { size 8{2} } } {}and i5 size 12{i rSub { size 8{5} } } {} are leaving it. By rearranging the terms, we get i 1 + i 3 + i 4 = i 2 + i 5 size 12{i rSub { size 8{1} } +i rSub { size 8{3} } +i rSub { size 8{4} } =i rSub { size 8{2} } +i rSub { size 8{5} } } {} is an alternative form of KCL: The sum of the current entering a node is equal to the sum of the currents leaving the node.

Currents at a node illustrating KCL. Note that KCL also applies to a closed boundary. This may be regarded as generalized case, because a node may be regarded as a closed surface shrunk to a point. In two dimensions, a closed boundary is the same as a closed path. As typically illustrated in the circuit of , the total current entering the closed surface is equal to the total current leaving the surface.

Appling KCL to a closed boundary. A simple application of KCL is combining current sources in parallel. The combined current is the algebraic sum of the current supplied by the individual sources. For examples, the current sources shown in (a) can be combined as in (b). The combined or equivalent current source can be found by applying KCL to node a. I T + I 2 = I 1 + I 3 size 12{I rSub { size 8{T} } +I rSub { size 8{2} } =I rSub { size 8{1} } +I rSub { size 8{3} } } {} or I T = I 1 − I 2 + I 3 size 12{I rSub { size 8{T} } =I rSub { size 8{1} } - I rSub { size 8{2} } +I rSub { size 8{3} } } {} A circuit cannot contain two different currents, I1 size 12{I rSub { size 8{1} } } {} and I2 size 12{I rSub { size 8{2} } } {}, in series, unless I1=I2 size 12{I rSub { size 8{1} } =I rSub { size 8{2} } } {}; otherwise KCL will be violated.

Current sources in parallel: a) origin circuit; b) equivalent circuit. Kirchhoff’s second law is based on the principle of conservation of energy: Kirchhoff’s voltage law (KVL) states that the algebraic sum of all voltages around a closed path (or loop) is zero. Expressed mathematically, KVL states that ∑ m = 1 M v m = 0 size 12{ Sum cSub { size 8{m=1} } cSup { size 8{M} } {v rSub { size 8{m} } =0} } {} Where M is the number of voltages in the loop (or the number of branches in the loop) and vm is the mth voltage. To illustrate KVL, consider the circuit in . The sign on each voltage is the polarity of the terminal encountered first as we travel around the loop. We can start with any branch and go around the loop either clockwise or counterclockwise. Suppose we start with the voltage source and go clockwise around the loop as shown; then voltages would be −v1 size 12{ - v rSub { size 8{1} } } {}, +v2 size 12{+v rSub { size 8{2} } } {}, +v3 size 12{+v rSub { size 8{3} } } {}, −v4 size 12{ - v rSub { size 8{4} } } {}, and +v5 size 12{+v rSub { size 8{5} } } {}, in that order. For example, as we reach branch 3, the positive terminal is met first; hence we have +v3 size 12{+v rSub { size 8{3} } } {}. For branch 4, we reach the negative terminal first; hence, −v4 size 12{ - v rSub { size 8{4} } } {}. Thus, KVL yields − v 1 + v 2 + v 3 − v 4 + v 5 = 0 size 12{ - v rSub { size 8{1} } +v rSub { size 8{2} } +v rSub { size 8{3} } - v rSub { size 8{4} } +v rSub { size 8{5} } =0} {} Rearranging terms gives v 2 + v 3 + v 5 = v 1 + v 4 size 12{v rSub { size 8{2} } +v rSub { size 8{3} } +v rSub { size 8{5} } =v rSub { size 8{1} } +v rSub { size 8{4} } } {} Which may be interpreted as Sum of voltage drops = sum of voltage rises This is an alternative form of KVL. Notice that if we had traveled counterclockwise, the result would have been +v1 size 12{+v rSub { size 8{1} } } {}, −v5 size 12{ - v rSub { size 8{5} } } {}, +v4 size 12{+v rSub { size 8{4} } } {}, −v3 size 12{ - v rSub { size 8{3} } } {}, and −v2 size 12{ - v rSub { size 8{2} } } {}, which is the same as before except that the sign are reversed. Hence, and remain the same.

A single loop circuit illustrating KVL. When voltage sources are connected in series, KVL can be applied to obtain the total voltage. The combined voltage is the algebraic sum of the voltage of the individual sources. For example, for the voltage shown in (a), the combined or equivalent voltage source in (b) is obtained by applying KVL. − V ab + V 1 + V 2 − V 3 = 0 size 12{ - V rSub { size 8{ ital "ab"} } +V rSub { size 8{1} } +V rSub { size 8{2} } - V rSub { size 8{3} } =0} {} or V ab = V 1 + V 2 − V 3 size 12{V rSub { size 8{ ital "ab"} } =V rSub { size 8{1} } +V rSub { size 8{2} } - V rSub { size 8{3} } } {} To avoid violating KVL, a circuit cannot contain two different voltages V1 size 12{V rSub { size 8{1} } } {} and V2 size 12{V rSub { size 8{2} } } {} in parallel unless V1=V2 size 12{V rSub { size 8{1} } =V rSub { size 8{2} } } {}.

Voltage source in series: a) original circuit, b) equivalent circuit.

SERIES RESISTORS AND VOLTAGE DIVISION The need to combine resistors in series or in parallel occurs so frequently that it warrants special attention. The process of combining the resistors is facilitated by combining two of them at a time. With this in mind, consider the single-loop circuit of the two resistors are in series, since the same current i flows in both of them. Applying Ohm’s law to each of the resistors, we obtain v1=iR1 size 12{v rSub { size 8{1} } = ital "iR" rSub { size 8{1} } } {}andv2=iR2 size 12{v rSub { size 8{2} } = ital "iR" rSub { size 8{2} } } {} If we apply KVL to the loop (moving in the ckockwise direction), we have − v + v 1 + v 2 = 0 size 12{ - v+v rSub { size 8{1} } +v rSub { size 8{2} } =0} {} Combining and , we get v = v 1 + v 2 = i ( R 1 + R 2 ) size 12{v=v rSub { size 8{1} } +v rSub { size 8{2} } =i \( R rSub { size 8{1} } +R rSub { size 8{2} } \) } {} or i = v ( R 1 + R 2 ) size 12{i= { {v} over { \( R rSub { size 8{1} } +R rSub { size 8{2} } \) } } } {}

A single loop circuit with two resistor in series. Notice that can be written as v = iR eq size 12{v= ital "iR" rSub { size 8{ ital "eq"} } } {} implying that the two resistors can be replaced by an equivalent resistor Req size 12{R rSub { size 8{ ital "eq"} } } {}; that is R eq = ( R 1 + R 2 ) size 12{R rSub { size 8{ ital "eq"} } = \( R rSub { size 8{1} } +R rSub { size 8{2} } \) } {} Thus, can be replaced by the equivalent circuit in . Two circuits in and are equivalent because they exhibit the same voltage-current relationship at the terminals a-b. An equivalent circuit such as the in is useful in simplying the analysis of a circuit. In general, The equivalent resistance of any number of resistors connected in series is the sum of the individual resistance. For N resistors in series then, R eq = R 1 + R 2 + ⋯ + R N = ∑ n = 1 N R n size 12{R"" lSub { size 8{ ital "eq"} } =R rSub { size 8{1} } +R rSub { size 8{2} } + dotsaxis +R rSub { size 8{N} } = Sum cSub { size 8{n=1} } cSup { size 8{N} } {R rSub { size 8{n} } } } {} To determine the voltage across each resistor in , we substitute into and obtain v 1 = R 1 R 1 + R 2 v , v 2 = R 2 R 1 + R 2 v alignl { stack { size 12{v rSub { size 8{1} } = { {R rSub { size 8{1} } } over {R rSub { size 8{1} } +R rSub { size 8{2} } } } v,} {} # v rSub { size 8{2} } = { {R rSub { size 8{2} } } over {R rSub { size 8{1} } +R rSub { size 8{2} } } } v {} } } {}

Equivalent circuit of the Figure 2.15 circuit. Note that the voltage v is divided among the resistor in direct proportion to their resistances; the larger the resistance, the larger the voltage drop. This is called the principle of voltage division, and the circuit in is called a voltage divider. In general, if a voltage divider has N resistors ( R1 size 12{R rSub { size 8{1} } } {}, R2 size 12{R rSub { size 8{2} } } {}, RN size 12{R rSub { size 8{N} } } {}) in series with the source voltage v, the nth resistor ( Rn size 12{R rSub { size 8{n} } } {}) will have a voltage drop of v n = R n R 1 + R 2 + ⋯ + R N v , size 12{v rSub { size 8{n} } = { {R rSub { size 8{n} } } over {R rSub { size 8{1} } +R rSub { size 8{2} } + dotsaxis +R rSub { size 8{N} } } } v,} {}

PARALLEL RESISTORS AND CURRENT DIVISION Consider the circuit in , where two resistors are connected in parallel and therefore have the same voltage across them. From Ohm’s law, v = i 1 R 1 = i 2 R 2 size 12{v=i rSub { size 8{1} } R rSub { size 8{1} } =i rSub { size 8{2} } R rSub { size 8{2} } } {} or i 1 = v R 1 , size 12{i rSub { size 8{1} } = { {v} over {R rSub { size 8{1} } } } ,} {} i 2 = v R 2 size 12{i rSub { size 8{2} } = { {v} over {R rSub { size 8{2} } } } } {} Applying KCL at node a gives the total current I as i = i1 + i2 Substituting into Equation (34), we get i = v R 1 + v R 2 = v ( 1 R 1 + 1 R 2 ) = v R eq size 12{i= { {v} over {R rSub { size 8{1} } } } + { {v} over {R rSub { size 8{2} } } } =v \( { {1} over {R rSub { size 8{1} } } } + { {1} over {R rSub { size 8{2} } } } \) = { {v} over {R rSub { size 8{ ital "eq"} } } } } {} where Req size 12{R rSub { size 8{ ital "eq"} } } {} is the equivalent resistance of the resistors in parallel: 1 R eq = 1 R 1 + 1 R 2 size 12{ { {1} over {R rSub { size 8{ ital "eq"} } } } = { {1} over {R rSub { size 8{1} } } } + { {1} over {R"" lSub { size 8{2} } } } } {} Or 1 R eq = R 1 + R 2 R 1 R 2 size 12{ { {1} over {R rSub { size 8{ ital "eq"} } } } = { {R rSub { size 8{1} } +R rSub { size 8{2} } } over {R rSub { size 8{1} } R rSub { size 8{2} } } } } {} Or R eq = R 1 R 2 R 1 + R 2 size 12{R rSub { size 8{ ital "eq"} } = { {R rSub { size 8{1} } R rSub { size 8{2} } } over {R rSub { size 8{1} } +R rSub { size 8{2} } } } } {} Thus, The equivalent resistance of two parallel resistors is equal to the product of their resistance divided by their sum.

Two resistor in parallel. It must be emphasized that this applies only to two resistors in parallel. From , if R1=R2 size 12{R rSub { size 8{1} } =R rSub { size 8{2} } } {}, then Req=R1/2 size 12{R rSub { size 8{ ital "eq"} } = {R rSub { size 8{1} } } slash {2} } {}. We can extend the result in to the general case of a circuit with N resistors in parallel. The equivalent resistance is 1 R eq = 1 R 1 + 1 R 2 + ... + 1 R N size 12{ { {1} over {R"" lSub { size 8{ ital "eq"} } } } = { {1} over {R rSub { size 8{1} } } } + { {1} over {R rSub { size 8{2} } } } + dotsaxis + { {1} over {R rSub { size 8{N} } } } } {} Note that Req size 12{R rSub { size 8{ ital "eq"} } } {} is always smaller than the resistance of the smallest resistor in the parallel combination. If R1=R2=...=RN=R size 12{R rSub { size 8{1} } =R rSub { size 8{2} } = "." "." "." =R rSub { size 8{N} } =R} {}, then R eq = R N size 12{R rSub { size 8{ ital "eq"} } = { {R} over {N} } } {} For example, if four 100 Ω size 12{ %OMEGA } {} resistors are connected in parallel, their equivalent resistance is 25 Ω size 12{ %OMEGA } {}. It is often more convenient to use conductance rather than resistance when dealing with resistors in parallel. From , the equivalent conductance for N resistors in parallel is G eq = G 1 + G 2 + . . . + G N size 12{G rSub { size 8{ ital "eq"} } =G rSub { size 8{1} } +G rSub { size 8{2} } + "." "." "." +G rSub { size 8{N} } } {} Where Geq=1/Req size 12{G rSub { size 8{ ital "eq"} } = {1} slash {R rSub { size 8{ ital "eq"} } } } {}, G1=1/R1 size 12{G rSub { size 8{1} } = {1} slash {R rSub { size 8{1} } } } {}, G2=1/R2 size 12{G rSub { size 8{2} } = {1} slash {R rSub { size 8{2} } } } {}, G3=1/R3 size 12{G rSub { size 8{3} } = {1} slash {R rSub { size 8{3} } } } {} … GN=1/RN size 12{G rSub { size 8{N} } = {1} slash {R rSub { size 8{N} } } } {}. states: The equivalent conductance of resistors connected in parallel is the sum of their individual conductances. This means that we may replace the circuit in with that in . Notice the similarity between and . The equivalent conductance of parallel resistors is obtained the same way as the equivalent resistance of resistors in series is obtained just the same way as the resistance of resistors in parallel. Thus the equivalent conductance Geq of N resistors in series (such as shown in ) is 1 G eq = 1 G 1 + 1 G 2 + 1 G 3 + ... + 1 G N size 12{ { {1} over {G rSub { size 8{ ital "eq"} } } } = { {1} over {G rSub { size 8{1} } } } + { {1} over {G rSub { size 8{2} } } } + { {1} over {G rSub { size 8{3} } } } + dotsaxis + { {1} over {G rSub { size 8{N} } } } } {} Given the total current i entering node a in , how do we obtain current i1 size 12{i rSub { size 8{1} } } {} and i2 size 12{i rSub { size 8{2} } } {}? We know that the equivalent resistor has the same voltage, or v = iR eq = iR 1 R 2 R 1 + R 2 size 12{v= ital "iR" rSub { size 8{ ital "eq"} } = { { ital "iR" rSub { size 8{1} } R rSub { size 8{2} } } over {R rSub { size 8{1} } +R rSub { size 8{2} } } } } {} Combining and results in i 1 = iR 2 R 1